I've become interested in all this talk of balanced power. After doing alot of reading I'm quite confused and was hoping someone would clear up a couple of things..
How does balanced power remove/reduce noise in the existing AC that is delivered to my house? I don't understand how this adds anything beyond normal AC filtering?
Assuming that f(x) represents the waveform for the AC power that is being delivered to my home from the power plant.
If g(x) represents the noise that is pickedup by the powerlines before the electricity is delivered to my wall than the total waveform delievired is f(x) + g(x)
Doesn't converting this 120/0 to +60/-60 just give you f(x)/2+g(x)/2 and -f(x)/2 -g(x)/2 on the +60 and -60 V outputs respectivly?...
It would seem that what you really want to end up with is f(x)/2+g(x)/2 and -f(x)/2 + g(x)/2 ... IE, balanced power with all the noise as common mode. But this would require the power to be delivered in a balanced format from the powerstation already.
Now if g2(x) represents the noise picked up after the AC is converted to balanced power than we should have
f(x)/2 + g(x)/2 + g2(x) and -f(x)/2 - g(x)/2 + g2(x) ... So g2(x) should cancle out at the rectifier..
Am I missing something? Is the majority of AC noise pickedup outside the wall on the way to the components?
Thanks inadvance,
--Chris
How does balanced power remove/reduce noise in the existing AC that is delivered to my house? I don't understand how this adds anything beyond normal AC filtering?
Assuming that f(x) represents the waveform for the AC power that is being delivered to my home from the power plant.
If g(x) represents the noise that is pickedup by the powerlines before the electricity is delivered to my wall than the total waveform delievired is f(x) + g(x)
Doesn't converting this 120/0 to +60/-60 just give you f(x)/2+g(x)/2 and -f(x)/2 -g(x)/2 on the +60 and -60 V outputs respectivly?...
It would seem that what you really want to end up with is f(x)/2+g(x)/2 and -f(x)/2 + g(x)/2 ... IE, balanced power with all the noise as common mode. But this would require the power to be delivered in a balanced format from the powerstation already.
Now if g2(x) represents the noise picked up after the AC is converted to balanced power than we should have
f(x)/2 + g(x)/2 + g2(x) and -f(x)/2 - g(x)/2 + g2(x) ... So g2(x) should cancle out at the rectifier..
Am I missing something? Is the majority of AC noise pickedup outside the wall on the way to the components?
Thanks inadvance,
--Chris
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