Hello,
I came up with a question when I was reading Ray Alden's "Speaker Building 201" and Vance Dickerson's LDC (7th Edition). This might be too simple a question for experts here, but I simply can't understand the answer the books provide.
Why does the sensitivity (db/2.83V) stay the same (i.e., 0 db change) in a double woofer system with woofers connected in a series, compared to a single woofer system?
Why not -3 db loss? The single woofer system uses 1W when the input voltage is 2.83V if the woofer's impedance is 8 ohm. According to my calculation, this implies that there is a current flow of 0.3534 amp. In a serial double woofer system, the current decreases to half of this due to the doubled impedance at the same 2.83V, and in turn the total watts consumed by the two woofers also decrease to a half (by the formula: W=V*I). Then, this turns into 10*log(0.5/1) = -3 db.
Am I wrong?
I came up with a question when I was reading Ray Alden's "Speaker Building 201" and Vance Dickerson's LDC (7th Edition). This might be too simple a question for experts here, but I simply can't understand the answer the books provide.
Why does the sensitivity (db/2.83V) stay the same (i.e., 0 db change) in a double woofer system with woofers connected in a series, compared to a single woofer system?
Why not -3 db loss? The single woofer system uses 1W when the input voltage is 2.83V if the woofer's impedance is 8 ohm. According to my calculation, this implies that there is a current flow of 0.3534 amp. In a serial double woofer system, the current decreases to half of this due to the doubled impedance at the same 2.83V, and in turn the total watts consumed by the two woofers also decrease to a half (by the formula: W=V*I). Then, this turns into 10*log(0.5/1) = -3 db.
Am I wrong?
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