A question thats been lingering....
Now, say you had a pair of speakers, with bi wire posts.
Now heres two scenarios.
1)Take those speakers and hook them up to...
*Each speaker gets a mono block, bi-wired, rated at 400watts RMS 8 ohms
(400 watts at 8 ohms SHARED between the lows-mid/high)
2)Take those same speakers and hook them up to..
*each speaker gets its own 2 ch amp, bi-amped, rated at 250 watts RMS 8 ohms.
(250 watts at 8 ohms DEDICATED to each low and mid/high)
I fully understand parallel and series wiring of speakers and the affect resistance has on amplifier output.(MECP installer 7+ years) But im just now really starting to enjoy home audio, and never have delt with bi wire posts on home speakers. I've never taken the time to measure the resistance of the speakers with my multimeter. (example, my 802s)
I know one set of posts is the woofers, the other is the mid/high. Is each set 8 ohms? or is the cabinet as a whole 8 ohms. (dont see how that could be unless they are 4 ohms each set series wired)
I also understand that to fully take advantage of the bi-amp setup you want to remove the crossovers from the cabinets to get the full power of the amps in the freq range for the selected speaker. (something im not interested in doing to my 802s or my pocket book)
So with that what will be the result to the above scenario, assuming, all speakers, amps and cables etc are equal?
My "theory" is IF:
The posts are 4 ohms each, the 250 watts at 8 (key word) ohms stereo amps in a bi-amp setup would yeild better results regarless if the crossovers were removed. (lets say 400 watts at 4 ohms for arguements sake)
Is there something toooo simple im missing here? Or just thinking about this to hard? :lol: Or maybe its more complex then i thought.
Discuss.
Now, say you had a pair of speakers, with bi wire posts.
Now heres two scenarios.
1)Take those speakers and hook them up to...
*Each speaker gets a mono block, bi-wired, rated at 400watts RMS 8 ohms
(400 watts at 8 ohms SHARED between the lows-mid/high)
2)Take those same speakers and hook them up to..
*each speaker gets its own 2 ch amp, bi-amped, rated at 250 watts RMS 8 ohms.
(250 watts at 8 ohms DEDICATED to each low and mid/high)
I fully understand parallel and series wiring of speakers and the affect resistance has on amplifier output.(MECP installer 7+ years) But im just now really starting to enjoy home audio, and never have delt with bi wire posts on home speakers. I've never taken the time to measure the resistance of the speakers with my multimeter. (example, my 802s)
I know one set of posts is the woofers, the other is the mid/high. Is each set 8 ohms? or is the cabinet as a whole 8 ohms. (dont see how that could be unless they are 4 ohms each set series wired)
I also understand that to fully take advantage of the bi-amp setup you want to remove the crossovers from the cabinets to get the full power of the amps in the freq range for the selected speaker. (something im not interested in doing to my 802s or my pocket book)
So with that what will be the result to the above scenario, assuming, all speakers, amps and cables etc are equal?
My "theory" is IF:
The posts are 4 ohms each, the 250 watts at 8 (key word) ohms stereo amps in a bi-amp setup would yeild better results regarless if the crossovers were removed. (lets say 400 watts at 4 ohms for arguements sake)
Is there something toooo simple im missing here? Or just thinking about this to hard? :lol: Or maybe its more complex then i thought.
Discuss.
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